Mastering Physics Solutions: Charging and Discharging a Capacitor in an R-C Circuit

Mastering Physics Solutions: Charging and Discharging a Capacitor in an R-C Circuit

On September 15, 2013, in Chapter 18: Basic Electric Circuits, by Mastering Physics Solutions

Part A = Zero
Part B = Ε
Part C = clockwise
Part D = the top plate
Part E = zero
Part F = q = CΕ
Part G = W = CΕ^2
Part H = q(t) = CΕ * (1 – e^(-t/RC))
Part I = I(t) = (Ε / R) * e^(-t/RC)
Part J = I(t) = (Ε / R) * e^(-t/RC)
Part K = I(t) = -q0 * e^(-t/RC) / (RC)

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Mastering Physics Solutions: Photoresistor

Mastering Physics Solutions: Photoresistor

On September 14, 2013, in Chapter 18: Basic Electric Circuits, by Mastering Physics Solutions

Part A = 9.0 v
Part B = 1.6 v
Part C = 0.39 v
Part D = Increase

What does the voltmeter read on a sunny day?
What does the voltmeter read on a cloudy day?
What does the voltmeter read at night?
Does the voltmeter reading increase or decrease as the light intensity increases?

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Mastering Physics Solutions: Finding Current by Changing Resistors

Mastering Physics Solutions: Finding Current by Changing Resistors

On March 7, 2013, in Chapter 18: Basic Electric Circuits, by Mastering Physics Solutions

Part A = 1.40 A Click to use the calculator/solver for this part of the problem

If the external resistance is then changed to R2 = 4.00 Ω, what is the value of the current I2 in the circuit?

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Mastering Physics Solutions: Kirchhoff’s Current Rule Ranking Task

Mastering Physics Solutions: Kirchhoff’s Current Rule Ranking Task

On March 6, 2013, in Chapter 18: Basic Electric Circuits, by Mastering Physics Solutions

Part A = A > (B = C)
Part B = C > (A = B)
Part C = D > A > (B = C)

Rank the resistors in the figure below (A to C) on the basis of the current that flows through them.
Rank the resistors in the figure below (A to C) on the basis of the current that flows through them.
Rank the resistors in the figure below (A to D) on the basis of the current that flows through them.

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Mastering Physics Solutions: Measuring the Potential of a Nonideal Battery

Mastering Physics Solutions: Measuring the Potential of a Nonideal Battery

On March 1, 2013, in Chapter 17: Electric Current and Resistance, by Mastering Physics Solutions

Part A = 88.4 V Click to use the calculator/solver for this part of the problem
Part B = 0.025641 V Click to use the calculator/solver for this part of the problem

A battery with EMF 90.0 V has internal resistance Rb = 8.48 Ω.

What is the reading Vv of a voltmeter having total resistance Rv = 475 Ω when it is placed across the terminals of the battery?
What is the maximum value that the ratio Rb / Rv may have if the percent error in the reading of the EMF of a battery is not to exceed 2.50%?

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Mastering Physics Solutions: Exercise 18.56

Mastering Physics Solutions: Exercise 18.56

On May 5, 2012, in Chapter 18: Basic Electric Circuits, by Mastering Physics Solutions

Part A = 12.1 ms Click to use the calculator/solver for this part of the problem
Part B = R = 1.12 kΩ Click to use the calculator/solver for this part of the problem
Part C = t = 10.1 ms Click to use the calculator/solver for this part of the problem
Part D = 595 J Click to use the calculator/solver for this part of the problem

A 10.8 µF capacitor in a heart defibrillator unit is charged fully by a 10500 V power supply.
Find the time constant.
Determine the resistance, R.
How much time does it take for the capacitor to lose 81 % of its stored energy?
If the paddles are left in place for many time constants, how much energy is delivered to the chest/heart area of the patient?

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