Part A = θTA – θ0
Part B = θTA
Part C = 18.7 W/m2
Part D = I0 = 2I = 5.81760
Part E = I2 = 0I0 = 0
Part F = See below
A beam of polarized light with intensity I0 and polarization angle θ0 strikes a polarizer with transmission axis θTA. What angle θ should be used in Malus’s law to calculate the transmitted intensity I1?Click for More...
Calcite (CaCO3) is a crystal with abnormally large birefringence…
Find the critical angle θce for e-waves in calcite.
Find the critical angle θco for o-waves in calcite.
Assume that the optical axis of the crystal is oriented horizontally (perpendicular to the direction of the incident ray). If unpolarized light shines into the calcite crystal shown and strikes the far side with θi = 40°, which of the following pictures correctly shows what will happen?
Is the transmitted ray (the one that passes into the air) polarized parallel to or perpendicular to the optical axis?
Now assume that the optical axis of the crystal is vertical (parallel to the direction of the incident ray). (The same figure still applies; just assume now that the optical axis is vertical.) Which of the following figures shows what would happen to the incident ray from Part C?