**Exercise 20.30**

Part A = 20 V

Part B = 4200 turns

Part C = 1.6 A

**Solutions Below:**

Part A

Express your answer using two significant figures.

The current transformation ratio for a transformer is equal to N_{primary} / N_{secondary}, where N is the number of turns (in the primary and secondary windings, respectively). The voltage transformation ratio is the opposite (N_{secondary} / N_{primary}). Note also that the voltage and ratios are the ratios of secondary to primary voltage or current. Since this problem gives us the current in both windings, start from there:

CurrentRatio = N_{primary} / N_{secondary}

(6 / 1) = N_{primary} / 700

N_{primary} = 4200

Since we have both the primary and secondary turns now, we can solve for the voltage ratio and determine the voltage across the secondary voltage:

VoltageRatio = N_{secondary} / N_{primary}

V_{secondary} / 120 = 700 / 4200

V_{secondary} = 20 V

20 V

Part B

Express your answer as an integer.

Just use the same formula as in Part A:

CurrentRatio = N_{primary} / N_{secondary}

(6 / 1) = N_{primary} / 700

N_{primary} = 4200

4200 turns

Part C

Express your answer using two significant figures.

We need to find the load resistance in the transformer to solve this problem. The load resistance is just the resistance in the secondary winding. We know both the secondary voltage and current from Part A:

R = V_{secondary} / I_{secondary}

R = 20 / 6

R = 3.333

Now we can plug this into the formula for power. Start by finding the maximum secondary current:

W = (I_{secondary})^{2} * R

290 = (I_{secondary})^{2} * 3.33

87 = (I_{secondary})^{2}

I_{secondary} = 9.33

Since the current transformation ratio is 6, just divide by 6:

9.33 / 6 = 1.56

It’s important to find the load resistance in order to correctly solve this problem. In case you try to solve by the formula W = V * I, you’ll find that you get an incorrect answer.

1.6 A