Mastering Physics Solutions: Board Pulled Out from under a Box

Board Pulled Out from under a Box

Part A = Fmin = μsg(m1 + m2)

Solution Below:

A small box of mass m1 is sitting on a board of mass m2 and length L . The board rests on a frictionless horizontal surface. The coefficient of static friction between the board and the box is μs. The coefficient of kinetic friction between the board and the box is, as usual, less than μs.

Throughout the problem, use g for the magnitude of the acceleration due to gravity. In the hints, use Ff for the magnitude of the friction force between the board and the box.

Part A

Find Fmin, the constant force with the least magnitude that must be applied to the board in order to pull the board out from under the the box (which will then fall off of the opposite end of the board).

Express your answer in terms of some or all of the variables μs, m1, m2, g, and L. Do not include Ff in your answer.

The friction force is downwards, but the surface is frictionless- the only friction is between the box and the board. So it’s just a matter of solving using the basic formula for static friction:

Fmin = μsg(m1 + m2)

Tagged with:  

Leave a Reply

Your email address will not be published.


*

You may use these HTML tags and attributes: <a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <strike> <strong>