Part A = F = -(μ * w) / ((μ * sin(θ)) – cos(θ))

Part B = 1/μ

Find the magnitude, F_{h}, of the force required to slide the lawnmower over the ground at constant speed by pushing the handle.

Find an expression for tan(θ_{critical})

Part A = F1 < F2 <= 2F1

Part B = 1/2F1 <= F3 < F1

The baggage handler now pushes a second box, identical to the first, so that it accelerates at a rate of 2a. How does the magnitude of the force F_{2} that the handler applies to this box compare to the magnitude of the force F_{1} applied to the first box?

Now assume that the baggage handler pushes a third box of mass m/2 so that it accelerates at a rate of 2a. How does the magnitude of the force F_{3} that the handler applies to this box compare to the magnitude of the force F_{1} applied to the first box?

Part A = (a + gsin(θ) + μgcos(θ)) / (g – a)

Find the ratio of the masses m_{1} / m_{2}.

Part A = (C = D) < (A = B) < (E = F) < (G = H) Note: see explanation for key of A-H

Part B = (C = D) < (A = B) < (E = F) < (G = H) Note: see explanation for key of A-H

Assume the elevator is at rest. Rank the magnitude of the forces.

Now, assume the elevator is moving upward at increasing speed. Rank the magnitude of the forces.

Part A = 254.8 N

Part B = 509.6 N

Part C = 509.6 N

Determine the force F required to lift the crate with constant speed.

Determine the tension in the upper chain.

Determine the tension in the lower chain.