Part A = -2.13 * 10^-5 C 
Part B = E = 1.02 * 10^-7
What must the charge (sign and magnitude) of a particle of mass 1.43 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 660 N/C?
What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?
Part A = 6.58 * 10^-13 N
Part B = negative x
Part C = attractive
Find the magnitude of the electric force, ignoring the sign, that the water molecule exerts on the chlorine ion.
What is the direction of the electric force?
Is this force attractive or repulsive?
Part A = 3.08*10^-14
If a drop is to be deflected a distance d = 0.320 mm by the time it reaches the end of the deflection plate, what magnitude of charge q must be given to the drop?
Click for More...Part A = 180 nC m
An electric field E = 100,000i N/C causes the 5.0 g point charge in the figure to hang at a 20° angle.
What is the charge on the ball?
Part A = 0.180 m
An infinitely long line of charge has a linear charge density of 8.00*10^−12 C/m. A proton is at distance 19.0 cm from the line and is moving directly toward the line with speed 1200 m/s.
How close does the proton get to the line of charge?